How to use integral with an implicit function defined through a sum

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Alex Dytso
Alex Dytso am 16 Jul. 2020
Beantwortet: Steven Lord am 16 Jul. 2020
Suppose we have a function define as follows:
fz=@(z) exp(-(z).^2/2);
g=@(y) sum ( v(1:n/2).*fz((y- v(n/2+1:n))));
here v is a vector of length n that is known and is used to define the fucntion g.
Now I want to integrated g from [-5,5] using command
integral(@(y) g(y), -5,5).
I, however, get an error that matrix dimensions must agree.
I get where the issue is. It occurs because I defined a function through a vector and pass another vector as input.
Is there a way of fixing this?
  2 Kommentare
Alex Dytso
Alex Dytso am 16 Jul. 2020
Bearbeitet: Alex Dytso am 16 Jul. 2020
Right, I forgot to say what it is. It's a vector of length n that is known and is used to define a function g.

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Steven Lord
Steven Lord am 16 Jul. 2020
By default, integral will call your function with an array and expects your function to return an array of the same size as the output. If you specify the name-value pair arguments 'ArrayValued', true in your integral call it will instead call your function with a scalar and expect an array as output.
v = 2:5;
y1 = integral(@(x) x.^v, 0, 1, 'ArrayValued', true)
y2 = integral(@(x) x.^v, 0, 1) % Throws an error

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