why is this code not giving the output?

1 Ansicht (letzte 30 Tage)
bsd
bsd am 26 Okt. 2011
Hai,
I have typed this code;
A=@(x)[cos(x),-sin(x),0;sin(x),cos(x),0;0,0,1]; B=@(x)(A*[10;20;30])
After the above step, matrix B is not displayed as a function of x. Why is it so? Are the two matrices getting multiplied or not?
I need the resultant matrix as a function of x, because I need to do integration for each term in the resultant matrix.
Here the matrix [10;20;30] need not be so, they can be any constant values.
Looking for your reply.
BSD

Melden Sie sich an, um diese Frage zu beantworten.

Antworten (1)

Fangjun Jiang
Fangjun Jiang am 26 Okt. 2011
A is an anonymous function. You need to modify your B.
A=@(x)[cos(x),-sin(x),0;sin(x),cos(x),0;0,0,1];
A(pi/2)
B=@(x)(A(x)*[10;20;30]);
B(pi/2)

Kategorien

Mehr zu Numeric Types finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by