Computing first derivative--image processing

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MLnoob5340
MLnoob5340 am 22 Nov. 2014
Kommentiert: Image Analyst am 23 Nov. 2014
I need help understanding computer first derivative
I don't understand how to derivative of [5 5 5 4 4 3 4 3 4 5 2 2 2 2 1 1 1]
is
[X 0 -1 0 -1 1 -1 1 1 -3 0 0 0 -1 0 0 X]

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Antworten (2)

Image Analyst
Image Analyst am 23 Nov. 2014
It's just the (n+1)st element minus the nth element. Same as you'd get from diff(). There are also imgradient(), and imgradientxy() functions in the Image Processing Toolbox.
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MLnoob5340
MLnoob5340 am 23 Nov. 2014
Okay! how would I find the second derivative do the same process again?
Image Analyst
Image Analyst am 23 Nov. 2014
Yeah, you can do that. What do you really want to do anyway? Why don't you post your image and say what you want to measure in it or do to it?

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Youssef Khmou
Youssef Khmou am 23 Nov. 2014
In general diff(X,n) of N by 1 vector returns an N-n by 1 vector, second derivative is diff(X,2), using gradient is better because it offers a possibility to choose the sample rate, if its 1 then :
d2x=gradient(gradient(x));

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