How to generate string without space at the beginning?

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YZ
YZ am 20 Nov. 2014
Beantwortet: Kelly Kearney am 20 Nov. 2014
FieldsLetter = repmat('Item_',16,1);
FieldsDigit = num2str(transpose(2:2:16),'%1d');
Fields = strcat(FieldsLetter, FieldsDigit);
The result from above code is Fields =
Item_ 2
Item_ 4
Item_ 6
Item_ 8
Item_10
Item_12
Item_14
Item_16
But what I want is Fields =
Item_2
Item_4
Item_6
Item_8
Item_10
Item_12
Item_14
Item_16
So how to generate string by using num2str without the space at the beginning? Thank you.

Akzeptierte Antwort

Kelly Kearney
Kelly Kearney am 20 Nov. 2014
Easier, you can just add the string part to the num2str format:
Fields = num2str((2:2:16)', 'Item_%d');
Of course, this right-justifies the final results, which may or may not matter to you. If you're looking to get a cell array of strings eventually, you can quickly trim the extra whitespace:
Fields = strtrim(cellstr(num2str((2:2:16)', 'Item_%d')))

Weitere Antworten (2)

Star Strider
Star Strider am 20 Nov. 2014
Change '%1d' to '%-1d'. The ‘-’ in front of the format descriptor left-justifies it.
FieldsLetter = repmat('Item_',8,1);
FieldsDigit = num2str(transpose(2:2:16),'%-1d');
Fields = strcat(FieldsLetter, FieldsDigit);

per isakson
per isakson am 20 Nov. 2014
Bearbeitet: per isakson am 20 Nov. 2014
num2str creates a rectangular character array. The "extra" space can be moved to the end of the string. If that's ok
Replace
FieldsDigit = num2str(transpose(2:2:16),'%1d');
by
FieldsDigit = num2str(transpose(2:2:16),'%-2d');
And read the documentation on num2str. Note:
'–' Left-justify. Example: %-5.2f
An alternative is to insert a leading zero
FieldsDigit = num2str(transpose(2:2:16),'%02d');

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