dection of a word inside a condition (if)

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Josep
Josep am 30 Okt. 2014
Kommentiert: Image Analyst am 30 Okt. 2014
I have programmed a code and I would like Matlab to recognise the word of materials (steel and aluminium). Any idea?
Following I put the code:
function y=kfgraf(r,Sut,material)
a=xlsread('kf.xls'); %Extret del webplotdigitizer
x1=a(1:67,1);
y1=a(1:67,2);
x2=a(1:65,3);
y2=a(1:65,4);
x3=a(1:64,5);
y3=a(1:64,6);
x4=a(1:63,7);
y4=a(1:63,8);
x5=a(1:59,9);
y5=a(1:59,10);
if material==steel && Sut<=0.4
i1=interp1(x1,y1,r,'spline');
y=i1
end
if material==steel && Sut>0.4 && Sut<=0.7
i1=interp1(x1,y1,r,'spline');
i2=interp1(x2,y2,r,'spline');
prop=((Sut-0.4)/(0.7-0.4))
y=i1+prop.*(i2-i1);
end
if material==steel && Sut>0.7 && Sut<=1
i1=interp1(x2,y2,r,'spline');
i2=interp1(x3,y3,r,'spline');
prop=((Sut-0.7)/(1-0.7))
y=i1+prop.*(i2-i1);
end
if material==steel && Sut>1 && Sut<=1.4
i1=interp1(x3,y3,r,'spline');
i2=interp1(x4,y4,r,'spline');
prop=((Sut-1)/(1.4-1))
y=i1+prop.*(i2-i1);
end
if material==steel && Sut>=1.4
i1=interp1(x4,y4,r,'spline');
y=i1
end
if material==aluminium
i1=interp1(x5,y5,r,'spline');
y=i1
end
end

Antworten (1)

per isakson
per isakson am 30 Okt. 2014
Bearbeitet: per isakson am 30 Okt. 2014
First idea:
>> material = 'steel';
>> strcmp( material, 'steel' )
ans =
1
  6 Kommentare
Josep
Josep am 30 Okt. 2014
Image Analyst
Image Analyst am 30 Okt. 2014
How are you calling this function? It requires input arguments so you can't just click the green triangle to run it. What the warning (not error) is saying is that you accept material via the input argument list but you don't use it because you overwrite it immediately with the line
material='steel';
so whatever you pass in is ignored completely, so you might as well not bother having it or passing it in.

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