How can i find a parameter in a formula when i have three series od data and wanna to find best answer for fourth parameter?

1 Ansicht (letzte 30 Tage)
I have three series od data for x,y and z I wanna find the fourth parameter m(like the best fit for it)in a Maxwell relaxation formula which that is:
z=2*m*x*y
and the series of other parameters are:
z=[0.0892 .158 0.890 1.26 2.47 3.64 6.71 11.6 18.1 27.7 42.0 65.4 97.5 141.0 196.0 283.0 440.0 661.0 863];
x=[0.05 0.628 0.0791 0.0995 0.125 0.158 0.199 0.25 0.315 0.396 0.5 0.628 0.79 0.995 1.25 1.58 1.99 2.5 3.15];
y=[1.42 1.78 2.25 2.83 3.56 4.49 5.65 7.08 8.79 11.01 13.87 17.46 21.8 27.16 33.75 42.34 53.53 67.03 84.11];
I will be grateful for helping me on this case.

Akzeptierte Antwort

Star Strider
Star Strider am 25 Okt. 2014
This works:
z=[0.0892 .158 0.890 1.26 2.47 3.64 6.71 11.6 18.1 27.7 42.0 65.4 97.5 141.0 196.0 283.0 440.0 661.0 863];
x=[0.05 0.628 0.0791 0.0995 0.125 0.158 0.199 0.25 0.315 0.396 0.5 0.628 0.79 0.995 1.25 1.58 1.99 2.5 3.15];
y=[1.42 1.78 2.25 2.83 3.56 4.49 5.65 7.08 8.79 11.01 13.87 17.46 21.8 27.16 33.75 42.34 53.53 67.03 84.11];
xy = [x; y];
fz= @(m,xy) 2.*m.*xy(1,:).*xy(2,:);
CF = @(m) sum((z - fz(m,xy)).^2);
m = fminsearch(CF, 1);
ze = fz(m, xy);
figure(1)
plot3(x, y, z, '+b')
hold on
plot3(x, y, ze, '-r')
hold off
grid on
view([30 40])
It estimates: m = 1.794 and seems visually to give a good fit.
  8 Kommentare

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by