Split a matrix into a two submatrixes by a condition

9 Ansichten (letzte 30 Tage)
Gino Franco
Gino Franco am 2 Okt. 2014
Bearbeitet: Mohammad Abouali am 7 Okt. 2014
Let "ex3" a matrix with an arbitrary length, which first column is gender (binary 0 or 1 for male o female), the second is age, the third is wage. How can I split this matrix into two submatrixes by gender using "for" and "if" functions? After that, i have to plot the wage versus the age, using plus sign (+) as a marker style for women and a circle (O) for men.
Anybody can give me an answer? I suppose that are few lines of code.
For the first part I've tried this:
for i=1:11
if ex3(i,1)==0
A=ex3(i,:)
else
B=ex3(i,:)
end
end
but this doesn't return me 2 matrixes, but a series of vectors.
  2 Kommentare
Iain
Iain am 2 Okt. 2014
Is there a reason you're restricting yourself to if and for?
Gino Franco
Gino Franco am 2 Okt. 2014
For learning reasons imposed by our teacher

Melden Sie sich an, um zu kommentieren.

Melden Sie sich an, um diese Frage zu beantworten.

Akzeptierte Antwort

Mohammad Abouali
Mohammad Abouali am 2 Okt. 2014
Bearbeitet: Mohammad Abouali am 2 Okt. 2014
If this is MATLAB programming class tell your teacher that using "for" and "if" is not necessary the correct way of learning matlab. Matlab has its own style of coding it's better to think that way. If it is a general programming class then the story is different.
So first the bad style MATLAB programming
female_ex3=[];
male_ex3=[];
for i=1:size(ex3,1)
if (ex3(i,1))==0)
male_ex3=[male_ex3;ex3(i,2:end)]; % Stripping of first column which tell you gender
else
female_ex3=[female_ex3;ex3(i,2:end)];
end
end
now a more accepted style in MATLAB
male_ex3=ex3( ex3(:,1)==0 , 2:end );
female_ex3=ex3( ex3(:,1)==1 , 2:end );
NOTE that I assumed 0 means male and 1 means female.

Weitere Antworten (1)

Iain
Iain am 2 Okt. 2014
This is the "simple" answer:
male = ex3(find(ex3(:,1) == 1),:);
female = ex3(find(ex3(:,1) == 0),:);
  1 Kommentar
Mohammad Abouali
Mohammad Abouali am 7 Okt. 2014
Bearbeitet: Mohammad Abouali am 7 Okt. 2014
You don't even need find . Look at the two last line of code in my answer.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Logical finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by