how to write if statement into for loop?

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lina
lina am 24 Mai 2014
Kommentiert: dpb am 24 Mai 2014
Hi all,
I have scattered data and I want to put them together and exclude the other which is not locate along the main axis, the statement of excluded data is
Longitude>43
and the loop is
for i=1:24
t_interp(:,i)=interp1(z(~isnan(z(:,i)),i),t(~isnan(t(:,i)),i),depth);
s_interp(:,i)=interp1(z(~isnan(z(:,i)),i),sal(~isnan(t(:,i)),i),depth);
end
i cant understand how to write it into the loop, I'm appreciate anyone can help me sorry for my bad English thank you in advance
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dpb
dpb am 24 Mai 2014
Think he means to how include the condition, SS...
@lina, what is the variable for Longitude? Need more info...
lina
lina am 24 Mai 2014
the code is for reading data from xls file, Longitude is exists in the file which include 24 stations between 30-45 longitudes the one I dont need it in loop is that >43 which equal to station 4 (by using x=find(Longitude>43) ans=4)
so i need to replace the station 4 values to nan (its also have some nan elements) to interpolate 23 station values
what should i do?

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dpb
dpb am 24 Mai 2014
Need storage arrangement to be precise, but if you have vectors of same length where Longitude is given for each element, then simply
z(Long>43)=nan;
will do the trick. Or, you could simply select the values to operate on and ignore the rest...
zprime=z(Long<43);
If z is a 2D array will need the (:) operator for the alternate dimension to pick up all rows or columns depending on whether the selected index is column or row, respectively.
Look up "logical addressing" in the documentation -- it's a key element of Matlab syntax and utilization.
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lina
lina am 24 Mai 2014
ok thank you
dpb
dpb am 24 Mai 2014
So did that solve the problem? If so, how about "Accepting" the answer; if not, show the actual storage scheme.

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